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authorpriyanka2015-06-24 15:03:17 +0530
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+//Engineering and Chemical Thermodynamics
+//Example 2.16
+//Page no :81
+
+clear ; clc ;
+//Given data:
+V_dot_2 = 0.001 ; //[m^3/kg]
+v_cap_2 = 0.001 ; //[m^3/kg], Specific volume of water
+z2 = 250 ; //[m] ; Taking ground as the reference level
+e_cap_2 = 9.8 * z2 ; //[kg*m^2/s^2]
+
+m_dot_2 = V_dot_2 / v_cap_2 ; //[kg/s]
+//Neglecting the kinetic energy ,frictional losses ftrom energy balance equation we have
+W_dot_s = m_dot_2 * e_cap_2 * 10^-3 ;
+disp(" Example: 2.16 Page no : 81") ;
+printf('\n Minimum power required is = %g kW',W_dot_s);