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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clc;
+clear;
+p1=30;//kPa
+d=1000;//kg/(m^3)
+r1=1;//m
+r2=0.5;//m
+//applying energy equation between points (1) and (2) and using the equation V^2=16*(r^2)
+V1=(16*(r1^2))^0.5;//m/sec
+V2=(16*(r2^2))^0.5;//m/sec
+p2=((p1*1000)+(d*((V1^2)-(V2^2)))/2)/1000;//kPa
+disp("kPa",p2,"The pressure at point (2) =")