initial commit / add all books

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+clc;

+clear;

+sw=64;//lb/ft^3; specific weight of water

+h=10;//ft

+a=3;//ft

+b=3;//ft

+

+//shape is triangular, hence hc=h-(a/3)

+hc=h-(a/3);

+A=(0.5*a*b);//ft^3; area of the right angled triangle

+fres=sw*hc*A;//lb

+Ixc=b*(a^3)/36;

+Ixyc=b*(a^2)*(b)/72;

+//according to the coordinate system taken yc=hc and xc=0

+yres=(Ixc/(hc*A))+hc;

+xres=(Ixyc/(hc*A));

+ydist=yres-hc;

+disp("lb",fres,"The resultant force on the area shown is=")

+disp("ft",yres,"yR=")

+disp("ft",xres,"xR=")

+disp("ft below the centroid of the area.",ydist,"ft to the right of and ",xres,"The centre of pressure is")