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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clc;
+clear;
+T0=288;//K
+p0=101;//kPa(abs)
+l=2;//m
+D=0.1;//m
+f=0.02;
+pd=45;//kPa(abs)
+f=0.02;
+m=1.65;//kg/sec
+lnew=l/2;//m
+
+x=f*l/D;
+//from this value of x, Ma at exit is found as
+Ma=0.7;
+//and p2/pcritical is found as
+pratio=1.5;
+//and, from example 11.12,
+prat=1.7;//where prat=p1/pcritical
+pfraction=0.76;//where pfraction=p1/p0,1
+//Hence,
+p2=pratio*(1/prat)*pfraction*p0;//kPa(abs)
+disp(Ma,"The Mach number at the exit=")
+disp("kPa(abs)",p2,"The back pressure required=") \ No newline at end of file