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authorpriyanka2015-06-24 15:03:17 +0530
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+ // The equation x^3-5*x+1==0 has real roots.
+ // the graph of this function can be observed here.
+xset('window',4);
+x=-2:.01:4; // defining the range of x.
+deff('[y]=f(x)','y=x^3-5*x+1'); //defining the cunction.
+y=feval(x,f);
+
+a=gca();
+
+a.y_location = "origin";
+
+a.x_location = "origin";
+plot(x,y) // instruction to plot the graph
+title(' y = x^3-5*x+1')
+
+// from the above plot we can infre that the function has roots between
+// the intervals (0,1),(2,3).
+// since we have been given the interval to be considered as (0,1)
+// a=0;b=1,
+
+
+ // Solution by secant method
+
+
+
+
+
+// since in the example 2.5 we have been asked to perform 4 itterations ,
+secant4(0,1,f) // we call a user-defined function 'bisection' so as to find the approximate
+// root of the equation with a defined permissible error.
+
+
+
+// hence the approximate root occured in secant method after 4 iterations is 0.201640 witin the permissible error of 10^-4,
+
+
+
+ // solution by regular falsi method
+
+
+// since in the example 2.5 we have been asked to perform 4 itterations ,
+
+regulafalsi4(0,1,f) // we call a user-defined function 'regularfalsi4' so as to find the approximate
+// root of the equation with a defined permissible error.
+
+
+
+// hence the approximate root occured in regularfalsi method after 4 iterations is 0.201640 witin the permissible error of 10^-4, \ No newline at end of file