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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+ // The equation x^3-5*x+1==0 has real roots.
+ // the graph of this function can be observed here.
+xset('window',15);
+x=-2:.01:4; // defining the range of x.
+deff('[y]=f(x)','y=x^3-5*x+1'); //defining the function.
+deff('[y]=fp(x)','y=3*x^2-5');
+deff('[y]=fpp(x)','y=6*x');
+y=feval(x,f);
+
+a=gca();
+
+a.y_location = "origin";
+
+a.x_location = "origin";
+plot(x,y) // instruction to plot the graph
+title(' y = x^3-5*x+1')
+
+// from the above plot we can infre that the function has roots between
+// the intervals (0,1),(2,3).
+// since we have been asked for the smallest positive root of the equation,
+// we are intrested on the interval (0,1)
+// a=0;b=1,
+
+
+// solution by multipoint iteration method
+
+// the approximate root after 3 iterations can be observed.
+
+
+multipoint_iteration31(0.5,f,fp)
+
+// hence the approximate root witin the permissible error of 10^-15 is .201640,
+
+
+
+multipoint_iteration33(0.5,f,fp)
+
+// hence the approximate root witin the permissible error of 10^-15 is .201640, \ No newline at end of file