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authorpriyanka2015-06-24 15:03:17 +0530
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+ // The equation x^3-5*x+1==0 has real roots.
+ // the graph of this function can be observed here.
+xset('window',10);
+x=-2:.01:4; // defining the range of x.
+deff('[y]=f(x)','y=x^3-5*x+1'); //defining the cunction.
+y=feval(x,f);
+
+a=gca();
+
+a.y_location = "origin";
+
+a.x_location = "origin";
+plot(x,y) // instruction to plot the graph
+title(' y = x^3-5*x+1')
+
+// from the above plot we can infre that the function has roots between
+// the intervals (0,1),(2,3).
+// since we have been asked for the smallest positive root of the equation,
+// we are intrested on the interval (0,1)
+
+
+ //sollution by muller method to 3 iterations.
+
+muller3(0,.5,1,f)
+