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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /497/CH4/EX4.2 | |
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-rwxr-xr-x | 497/CH4/EX4.2/Chap4_Ex2.sce | 50 |
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diff --git a/497/CH4/EX4.2/Chap4_Ex2.sce b/497/CH4/EX4.2/Chap4_Ex2.sce new file mode 100755 index 000000000..53e00c02a --- /dev/null +++ b/497/CH4/EX4.2/Chap4_Ex2.sce @@ -0,0 +1,50 @@ +//Kunii D., Levenspiel O., 1991. Fluidization Engineering(II Edition). Butterworth-Heinemann, MA, pp 491
+
+//Chapter-4, Example 2, Page 108
+//Title: Design of a Tuyere Distributor
+//==========================================================================================================
+clear
+clc
+
+//INPUT
+lor=0.1;//Minimum allowable tuyere spacing in m
+uorm=30;//Maximum allowable jet velocity from the tuyere in m/s
+uo=0.4;//Superficial velocity of gas in m/s
+uor=30.2;//Gas velocity through orifice,from Exa 1, in m/s
+Cd=0.6;//Dicharge coefficient from Exa 1
+rhog=3.6//Density of gas in kg/m^3
+pi=3.1428;
+
+//CALCULATION
+Nor=1/(lor^2);//Calculation of number of orifices per unit area by assuming minimum spacing for tuyeres
+dor={(4/pi)*(uo/uor)*(1/Nor)}^0.5;//Calculation of diameter of inlet orifiec by using Eqn.(13)
+
+//Computation of diameter of hole for different number of holes per tuyere
+q=(lor^2)*uo;//Volumetric flow rate in m^3/s
+Nh=[8;6;4];//Different number of holes per tuyere
+n=length(Nh);
+i=1;
+while i<=n
+ dh(i)=((((q/Nh(i))*(4/pi))/uorm)^0.5);//Calculation of diameter of holes
+ i=i+1;
+end
+deltaph=(rhog/2)*((uor/Cd)^2);
+
+//OUTPUT
+printf('\nNumber of holes(number of holes/tuyeres)');
+printf('\tDiameter of hole(m)');
+j=1;
+while j<=n
+ mprintf('\n%f',Nh(j));
+ mprintf('\t\t\t\t\t%f',dh(j));
+ j=j+1;
+end
+printf('\nThe design chosen is as follows');
+printf('\n\tTuyeres are as shown in Fig.2(b),page 97');
+mprintf('\n\tNumber of holes = %f(Since rectangular pitch is chosen for tuyeres)',Nh(2));
+mprintf('\n\tDiameter of hole = %fm',dh(2));
+mprintf('\n\tDiameter of incoming high-pressure-drop orifice = %fm ID',dor);
+printf('\nChecking the pressure drop in tuyeres');
+mprintf('\nSince pressure drop of %fPa gives sufficiently high distributor pressure drop as seen in Exa.1, use of inlet orifice can be dispensed.',deltaph);
+
+//====================================END OF PROGRAM ======================================================
\ No newline at end of file |