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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//All the quantities are expressed in SI units
+
+M1 = 8; //mach number
+alpha = 15*%pi/180; //anlge of attack
+theta= alpha;
+gam = 1.4;
+
+//(a)
+//for M = 8
+v1 = 95.62*%pi/180;
+v2 = v1 + theta;
+
+//from Appendix C
+M2 = 14.32;
+
+//from Appendix A, for M1 = 8 and M2 = 14.32
+p_ratio = 0.9763e4/0.4808e6;
+
+//from eq.(11.22)
+Cp2 = 2/gam/M1^2*(p_ratio - 1);
+
+//for M1 = 8 and theta = 15
+b = 21*%pi/180;
+Mn_1 = M1*sin(b);
+
+//for this value of Mn,1, from appendix B
+p_ratio2 = 9.443;
+
+//thus
+Cp3 = 2/gam/M1^2*(p_ratio2 - 1);
+
+c_n = Cp3 - Cp2;
+
+c_l = c_n*cos(alpha);
+
+c_d = c_n*sin(alpha);
+
+L_by_D = c_l/c_d;
+
+printf("\nRESULTS\n---------\n(a) The exact results from the shock-expansion theory are:\n Cp2 = %1.4f\n Cp3 = %1.4f\n cl = %1.4f\n cd = %1.4f\n L/D = %1.2f\n",Cp2,Cp3,c_l,c_d,L_by_D)
+
+//(b)
+//from Newtonian theory, by eq.(14.9)
+Cp3 = 2*sin(alpha)^2;
+Cp2 = 0;
+c_l = (Cp3 - Cp2)*cos(alpha);
+c_d = (Cp3 - Cp2)*sin(alpha);
+L_by_D = c_l/c_d;
+
+printf("\n(b) The results from Newtonian theory are:\n Cp2 = %1.4f\n Cp3 = %1.4f\n cl = %1.4f\n cd = %1.4f\n L/D = %1.2f\n",Cp2,Cp3,c_l,c_d,L_by_D) \ No newline at end of file