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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /49/CH6/EX6.3 | |
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Diffstat (limited to '49/CH6/EX6.3')
-rwxr-xr-x | 49/CH6/EX6.3/ex3.sce | 31 |
1 files changed, 31 insertions, 0 deletions
diff --git a/49/CH6/EX6.3/ex3.sce b/49/CH6/EX6.3/ex3.sce new file mode 100755 index 000000000..1da1ada8b --- /dev/null +++ b/49/CH6/EX6.3/ex3.sce @@ -0,0 +1,31 @@ +//CHAPTER 6 _ PRESSURE AND SOUND MEASUREMENT
+//Caption : Elastic Transducers
+// Example 3 // Page 337
+Sa=1000
+disp("Sa=1000") //('Enter the sensitivity of LVDT =:')
+//Properties of diaphragm
+E=200*10^9 //('Enter the value of modulus of elasticity=:')
+disp("E=200*10^9 ")
+v=0.3 //('Enter the Poissons ratio=:')
+disp("v=0.3 ")
+d=0.2 //('Enter the diameter of diaphragm=:')
+disp("d=0.2 ")
+R=d*(1/2);
+P_max=2*10^6 //('What is the maximum pressure?')
+disp("P_max=2*10^6 ")
+p=7800 //('What is the density of steel?')
+disp("Thickness is given by:")
+disp("t=(3*P_max*R^4*(1-v^4)/(4*E))^(1/4);")
+t=(3*P_max*R^4*(1-v^4)/(4*E))^(1/4)
+T=t*1000;
+printf('Thickness is %1.1f mm\n',T)
+//To calculate the lowest pressure in kPa which may be sensed by this instrument , resolution and the natural frequency of the diaphragm
+y=.001 //('Enter the l)east value of measurement=:')
+p_min=(y*16*E*t^3)/(3*R^4*(1-v^2)*Sa)
+printf('So the minimum pressure and resolution is %d Pa \n',p_min)
+f=(10.21/R^2)*((E*t^2)/(12*(1-v^2)*p))^(1/2)
+printf('The natural frequency of diaphragm is %fd Hz',f)
+
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