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+//Chemical Engineering Thermodynamics

+//Chapter 14

+//Thermodynamics of Chemical Reactions

+

+//Example 14.12

+clear;

+clc;

+

+//Given

+//C + 2H2 - CH4

+//Basis: 1 Kgmole of C fed

+T = 1000;//Temperature in K

+P1 = 2;//Pressure in atm

+del_F = 4580;//Standard free energy in Kcal/Kgmole

+

+

+//To Calculate the maximum CH4 concentration under the condition of 2 atm and the  quantity of methane obtained if pressure is 1 atm

+Ka = %e^(-del_F/(R*T));//Equilibrium constant

+//In relation (d) (page no 339) p_H2 = p (say)

+p = poly(0,'p');

+q = Ka*(p^2)+p-P1;

+r = roots(q);

+p_H2 = r(2);//partial pressure of H2

+p_CH4 = P1-p_H2;//partial pressure of CH4

+X_H2 = p_H2*100/P1;//mole percent of H2

+X_CH4 = p_CH4*100/P1;//mole percent of CH4

+mprintf('Under the conditions of 2 atm and 1000 K,the maximum CH4 concentration is %f percent and further increase is not pssible',X_CH4);

+//Now.pressure has become

+P2 = 1;//in atm

+q = Ka*(p^2)+p-P2;

+r = roots(q);

+p_H2 = r(2);//partial pressure of H2

+p_CH4 = P2-p_H2;//partial pressure of CH4

+X_H2 = p_H2*100/P2;//mole percent of H2

+X_CH4 = p_CH4*100/P2;//mole percent of CH4

+mprintf('\n\n Under the conditions of 1 atm and 1000 K,Methane = %f percent and Hydrogen = %f percent',X_CH4,X_H2);

+//end
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