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+//Chemical Engineering Thermodynamics

+//Chapter 11

+//Liquefaction of Gases

+

+//Example 11.1

+clear;

+clc;

+

+//Given

+P1 = 8.74;//Initial pressure in Kgf/sq cm

+P2 = 2.41;//Final pressure in Kgf/sq cm

+H1 = 327.13;//Enthalpy of inlet stream in Kcal/Kg

+H2 = H1;//Enthalpy of exit stream in Kcal/Kg ,since throttling is isenthalpic

+Hl = 26.8;//Enthalpy of liquid  at the final condition in Kcal/Kg

+Hg = 340.3;//Enthalpy of gas at the final condition  in Kcal/Kg

+vl = 152*10^-5;//Specific volume of liquid at the final condition in cubic meter/Kg

+vg = 0.509;//Specific volume of gas at the final condition in cubic meter/Kg

+v1 = 0.1494;//Initial specific volume in cubic meter/Kg

+

+//To Calculate the dryness fraction of exit stream and the ratio of upstream to downstream diameters

+//(i)Calculation of the dryness fraction of exit stream

+//From equation 3.13(a) (page no 82)

+x = (H2- Hl)/(Hg-Hl);

+mprintf('(i)The dryness fraction of the exit stream is %f',x);

+

+//(ii)Calculation of the ratio of upstream to downstream pipe diameters

+//From equation 3.13(b) (page no 82)

+v2 = (vl*(1-x))+(x*vg);//Total specific volume at the final condition in cubic meter/Kg

+//u1 = u2; since KE changes are negligible

+//From continuity equation: A2/A1 = D2^2/D1^2 = v2/v1 ; let required ratio,r = D2/D1;

+r = (v2/v1)^(1/2);

+mprintf('\n (ii)The ratio of upstream to downstream diameters  is %f',r);

+//end
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