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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /479/CH10/EX10.5 | |
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Diffstat (limited to '479/CH10/EX10.5')
| -rwxr-xr-x | 479/CH10/EX10.5/Example_10_5.sce | 22 |
1 files changed, 22 insertions, 0 deletions
diff --git a/479/CH10/EX10.5/Example_10_5.sce b/479/CH10/EX10.5/Example_10_5.sce new file mode 100755 index 000000000..3bc48b05a --- /dev/null +++ b/479/CH10/EX10.5/Example_10_5.sce @@ -0,0 +1,22 @@ +//Chemical Engineering Thermodynamics
+//Chapter 10
+//Compressor
+
+//Example 10.5
+clear;
+clc;
+
+//Given
+P1 = 1;//Initial pressure in Kgf/sq cm
+P4 = 200;//Final pressure in Kgf/sq cm
+n = 4;//no of stages
+
+//To find out the presure between stages
+r = (P4/P1)^(1/n);//Compression ratio
+P2 = r*P1;
+mprintf('The pressure after 1st stage is %f Kgf/sq cm',P2);
+P3 = r*P2;
+mprintf('\n The pressure after 2nd stage is %f Kgf/sq cm',P3);
+P4 = r*P3;
+mprintf('\n The pressure after 3rd stage is %f Kgf/sq cm',P4);
+//end
\ No newline at end of file |