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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /479/CH10/EX10.2 | |
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initial commit / add all books
Diffstat (limited to '479/CH10/EX10.2')
-rwxr-xr-x | 479/CH10/EX10.2/Example_10_2.sce | 24 | ||||
-rwxr-xr-x | 479/CH10/EX10.2/Example_10_2.txt | 3 |
2 files changed, 27 insertions, 0 deletions
diff --git a/479/CH10/EX10.2/Example_10_2.sce b/479/CH10/EX10.2/Example_10_2.sce new file mode 100755 index 000000000..54e541a61 --- /dev/null +++ b/479/CH10/EX10.2/Example_10_2.sce @@ -0,0 +1,24 @@ +//Chemical Engineering Thermodynamics
+//Chapter 10
+//Compressor
+//Example 10.2
+clear;
+clc;
+
+//Given
+P1 = 1;//Initial pressure in atm
+P2 = 29;//Final pressure in atm
+C = 0.05;//Clearance
+y = 1.4;//gamma of air
+
+//To calculate the volumetric efficiency and the maximum possible pressure that can be attained in a single stage
+//(i)Calulation of volumetric efficiency
+//From equation 10.11 (page no 194)
+V_E = 1+C-C*(P2/P1)^(1/y);
+mprintf('(i)Volumetric efficiency is %f percent',V_E*100);
+
+//(ii)Calculation of maximum pressure
+V_E = 0;//Minimum efficiency
+P2 = P1*(((1+C-V_E)/C)^y);
+mprintf('\n (ii)The maximum possible pressure attained is %f atm',P2);
+//end
\ No newline at end of file diff --git a/479/CH10/EX10.2/Example_10_2.txt b/479/CH10/EX10.2/Example_10_2.txt new file mode 100755 index 000000000..bac31c4c3 --- /dev/null +++ b/479/CH10/EX10.2/Example_10_2.txt @@ -0,0 +1,3 @@ +For example 10.2 (ii),
+The answer given in the book is 79 atm but i am getting 70.97 atm.
+There might be some calculation mistake in the book.
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