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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
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| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /479/CH10/EX10.1/Example_10_1.sce | |
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diff --git a/479/CH10/EX10.1/Example_10_1.sce b/479/CH10/EX10.1/Example_10_1.sce new file mode 100755 index 000000000..c18726e16 --- /dev/null +++ b/479/CH10/EX10.1/Example_10_1.sce @@ -0,0 +1,33 @@ +//Chemical Engineering Thermodynamics
+//Chapter 10
+//Compressor
+//Example 10.1
+clear;
+clc;
+
+//Given
+V1 = 2.7;//flow rate of CO2 in cubic meter/min
+T1 = 273-51;//temperature in K
+P1 = 1;//initial pressure in Kgf/sq cm
+P2 = 10;//final pressure in Kgf/sq cm
+y = 1.3;//gamma
+v1 = 0.41;//specific volume in cubic meter/Kg
+H1 = 158.7;// initial enthalpy in Kcal/Kg
+H2 = 188.7;//final enthalpy in Kcal/Kg
+
+//process is isentropic
+//To calculate the horsepower required
+
+//(i)Assuming ideal gas behaviour
+//From equation 10.3 (page no 189)
+W = (y/(y-1))*(P1*1.03*10^4*V1)*(1-(P2/P1)^((y-1)/y));//work in m Kgf/min
+W1 = W/4500;
+mprintf('(i)The horsepower required is %f hp',W1);
+
+//(ii)Using the given data for CO2
+//From equation 10.2 (page no 189)
+W = -(H2 - H1);//work in Kcal/Kg
+M = V1/v1;//Mass rate of gas in Kg/min
+W1 = W*M*(427/4500);
+mprintf('\n (ii)Compressor work is %f hp',W1);
+//end
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