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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /45/CH6/EX6.7/example_6_7.sce | |
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initial commit / add all books
Diffstat (limited to '45/CH6/EX6.7/example_6_7.sce')
-rwxr-xr-x | 45/CH6/EX6.7/example_6_7.sce | 76 |
1 files changed, 76 insertions, 0 deletions
diff --git a/45/CH6/EX6.7/example_6_7.sce b/45/CH6/EX6.7/example_6_7.sce new file mode 100755 index 000000000..3f9409619 --- /dev/null +++ b/45/CH6/EX6.7/example_6_7.sce @@ -0,0 +1,76 @@ +//example 6.7 +clc; +clear; +a=0; +b=0; +q=0; +//aa=input(" Enter the first no (in decimal) :"); +//bb=input(" Enter the number from which first no has to substracted:"); +aa=175; +bb=118; +while(aa>0) // converting the inputs in to binary numbers + x=modulo(aa,2); + a= a + (10^q)*x; + aa=aa/2; + aa=floor(aa); + q=q+1; +end +q=0; +while(bb>0) + x=modulo(bb,2); + b= b + (10^q)*x; + bb=bb/2; + bb=floor(bb); + q=q+1; +end +printf(' \n The binary equivalent of first no is %f\n\n',a); +printf(' The binary equivalent of secnd no is %f\n\n',b); +for i=1:8 + a1(i)=modulo(a,10); + a=a/10; + a=round(a); + b1(i)=modulo(b,10); + b=b/10; + b=round(b); +end + +car(1)=0; +for i=1:8 + c1(i)=car(i)+a1(i)+ b1(i);//adding the binary numbers (binary addtion) + if c1(i)== 2 then + car(i+1)= 1; + c1(i)=0; + elseif c1(i)==3 then + car(i+1)= 1; + c1(i)=1; + else + car(i+1)=0; + end +end +c1(9)=car(9); +re=0; +format('v',18); +for i=1:8 + re=re+(c1(i)*(10^(i-1))) +end +printf('If only 8 bits are taken the result will be as shown below \n\n'); +printf(' and the sum of given two binary numbers will be %f\n\n',re ); +q=1; +b=0; +f=0; +a=re; +while(a>0) //converting the binary output to hexadecimal + r=modulo(a,10); + b(1,q)=r; + a=a/10; + a=floor(a); + q=q+1; +end +for m=1:q-1 + c=m-1; + f = f + b(1,m)*(2^c); +end +printf(' Sum in decimal notation is %d\n\n',f); +hex=dec2hex(f); +printf(' The sum in hexadecimal notation is %sH \n',hex); +printf(' \n with an overflow of %d\n\n',car(9));
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