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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /409/CH27/EX27.3 | |
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-rwxr-xr-x | 409/CH27/EX27.3/Example27_3.sce | 19 |
1 files changed, 19 insertions, 0 deletions
diff --git a/409/CH27/EX27.3/Example27_3.sce b/409/CH27/EX27.3/Example27_3.sce new file mode 100755 index 000000000..b639cb0be --- /dev/null +++ b/409/CH27/EX27.3/Example27_3.sce @@ -0,0 +1,19 @@ +clear ; +clc; +// Example 27.3 +printf('Example 27.3\n\n'); +//page no. 845 +// Solution + +// Given +p_plant = 20 ;// Power generated by plant-[MW] +h = 25 ;// Height of water level - [m] +V = 100 ;// Flow rate of water -[cubic metre/s] +d_water = 1000 ;// Density of water - [ 1000 kg / cubic metre] +g = 9.807 ;// Acceleration due to gravity-[m/square second] + +M_flow = V*d_water ;// Mass flow rate of water -[kg/s] +del_PE = M_flow*g*h ;// Potential energy change of water per second -[W] +eff = (p_plant*10^6) /(del_PE) ;// Efficiency of plant + +printf(' Efficiency of plant is %.2f .\n',eff) ;
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