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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /409/CH25/EX25.1/Example25_1.sce | |
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diff --git a/409/CH25/EX25.1/Example25_1.sce b/409/CH25/EX25.1/Example25_1.sce new file mode 100755 index 000000000..dac0fae14 --- /dev/null +++ b/409/CH25/EX25.1/Example25_1.sce @@ -0,0 +1,18 @@ +clear ; +clc; +// Example 25.1 +printf('Example 25.1\n\n'); +//page no. 766 +// Solution Fig. E25.1 + +// Given +// C(s) + O2(g) --> CO2(g) (A) +// CO(g) + (1/2)(O2)(g) --> CO2 (g) (B) +Qa = -393.51 ;// Heat of reaction of reaction (a) - [kJ/g mol C] +Qb = -282.99 ;// Heat of reaction of reaction (b) - [kJ/g mol CO] +del_Ha = Qa ;// Change in enthalpy of reaction A - [kJ/g mol C] +del_Hb = Qb ;// Change in enthalpy of reaction B - [kJ/g mol CO] + +// According to Hess's Law , subtract reaction (B) from reaction (A) , subtract corresponding del_H's to get enthalpy of formation of reaction (C)- C(s) + (1/2)*O2 --> CO(g) , therefore +del_Hfc = del_Ha - del_Hb ;// Standard heat of formation of CO - [kJ/g mol C] +printf('Standard heat of formation of CO is %.2f kJ/g mol C.',del_Hfc) ;
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