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authorpriyanka2015-06-24 15:03:17 +0530
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+clear;
+clc;
+printf("\t\t\tExample Number 8.2\n\n\n");
+// heat transfer between black surfaces
+// Example 8.2 (page no.-389-390)
+// solution
+
+L = 1;// [m] length of black plate
+W = 0.5;// [m] width of black plate
+T1 = 1000+273;// [K] first plate temperature
+T2 = 500+273;// [K] second plate temperature
+sigma = 5.669*10^(-8);// [W/square meter K^(4)]
+// the ratios for use with figure 8-12(page no.-386) are
+Y_by_D = W/W;
+X_by_D = L/W;
+// so that
+F12 = 0.285;// radiation shape factor
+// the heat transfer is calculated from
+q = sigma*L*W*F12*(T1^(4)-T2^(4));
+printf("net radiant heat exchange between the two plates is %f kW",q/1000);
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