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authorpriyanka2015-06-24 15:03:17 +0530
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+clear;
+clc;
+
+// Illustration 6.7
+// Page: 207
+
+printf('Illustration 6.7 - Page: 207\n\n');
+
+// solution
+
+//****Data****//
+// Air
+G_prime = 1.10;// [kg/square m.s]
+viscocity_G = 1.8*10^(-5);// [kg/m.s]
+ScG = 0.6;// [for air water mixture]
+Temp1 = 273+20;// [K]
+
+// Water
+L_prime = 5.5;// [kg/square m.s]
+//*****//
+
+// Air:
+Ma = 29;// [kg/kmol]
+G = G_prime/Ma;// [kmol/square m.s]
+Density_G = (Ma/22.41)*(273/Temp1);
+Cpa = 1005;// [N.m/kg.K]
+PrG = 0.74;
+
+// Liquid:
+kth = 0.587;// [W/m.K]
+Cpb = 4187;// [N.m/kg.K]
+viscocity_L = 1.14*10^(-3);// [kg/m.s]
+
+// From Table 6.5 (Pg 206)
+Ds = 0.0725;// [m]
+beeta = 1.508*(Ds^0.376);
+shiLtW = (2.09*10^(-6))*(737.5*L_prime)^beeta/(Ds^2);// [square m/cubic m]
+shiLsW = 2.47*10^(-4)/(Ds^1.21);// [square m/cubic m]
+shiLoW = shiLtW-shiLsW;// [square m/cubic m]
+// From Table 6.4 (Pg 205)
+m = 34.03;
+n = 0;
+p = 0.362;
+aAW = m*(808*G_prime/Density_G^0.5)^(n)*L_prime^p;// [square m/cubic m]
+// From Eqn. 6.75
+aVW = 0.85*aAW*shiLtW/shiLoW;// [square m/cubic m]
+// From Table 6.3
+e = 0.74;
+eLo = e-shiLtW;
+// From Eqn. 6.70
+deff('[y] = f11(Fg)','y = ((Fg*ScG^(2/3))/G)-1.195*((Ds*G_prime)/(viscocity_G*(1-eLo)))^(-0.36)');
+Fg = fsolve(1,f11);// [kmol/square m.s]
+// Since the liquid is pure water. It has no mass trnsfer coeffecient.
+// For such process we need convective heat transfer coeffecient for both liquid & gas.
+// Asuming Jd = Jh
+// From Eqn. 6.70
+Jh = 1.195*((Ds*G_prime)/(viscocity_G*(1-eLo)))^(-0.36);
+Hg = Jh*Cpa*G_prime/(PrG^(2/3));// [W/square m.K]
+PrL = Cpb*viscocity_L/kth;
+// Heat transfer analog of Eqn. 6.72
+Hl = 25.1*(kth/Ds)*(Ds*L_prime/viscocity_L)^0.45*PrL^0.5;// [W/square m.K]
+printf("The volumetric coeffecients are\n");
+printf("Based on Gas Phase %f W/cubic m.K\n",Hg*aVW);
+printf("based on Liquid Phase %f W/cubic m.K\n",Hl*aVW); \ No newline at end of file