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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /389/CH4/EX4.6 | |
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Diffstat (limited to '389/CH4/EX4.6')
| -rwxr-xr-x | 389/CH4/EX4.6/Example4_6.sce | 40 |
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diff --git a/389/CH4/EX4.6/Example4_6.sce b/389/CH4/EX4.6/Example4_6.sce new file mode 100755 index 000000000..59175e489 --- /dev/null +++ b/389/CH4/EX4.6/Example4_6.sce @@ -0,0 +1,40 @@ +clear;
+clc;
+
+// Illustration 4.6
+// Page: 100
+
+printf('Illustration 4.6 - Page: 100\n\n');
+
+// solution
+
+//***Data***//
+// a = N2
+// For N2 at 300K
+viscosity1 = 1.8*10^(-5);// [kg/m.s]
+Pt1 = 10133;// [N/square m.sec]
+T = 300;// [K]
+z = 0.0254;// [m]
+T2 = 393;// [K]
+//***********//
+
+Ma = 28.02;// [kg/kmol]
+R = 8314;// [J/K.kgmol]
+//From Eqn 4.22
+lambda = (3.2*viscosity1/Pt1)*(R*T/(2*(%pi)*Ma))^0.5;
+d = 10^(-4);// [m]
+d_by_lambda = d/lambda;
+// Kundsen flow will not occur
+// N2 flow corresponding to 9 cubic ft/square ft.min at 300K & 1 std atm = 0.0457 cubic m/square m.min
+Na1 = 0.0457*(273/T)*(1/22.41);// [kmol/square m.s]
+Pt1_diff_Pt2 = 2*3386/13.6;// [N/square m]
+Ptav = Pt1+(Pt1_diff_Pt2/2);// [N/square m]
+// From Eqn. 4.26
+k1 = Na1*R*T*z/(Ptav*(Pt1_diff_Pt2));// [m^4/N.s]
+
+//For N2 at 393K
+viscosity2 = 2.2*10^(-5);// [kg/m.s]
+k2 = (k1*viscosity1)/(viscosity2);// [m^4/N.s]
+// From Eqn 4.26
+Na = (k2*Ptav*Pt1_diff_Pt2)/(R*T2*z);// [kmol/square m.s]
+printf("Flow rate to be expected is %e kmol/square m.s",Na);
\ No newline at end of file |