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| author | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
| commit | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch) | |
| tree | 449d555969bfd7befe906877abab098c6e63a0e8 /3886/CH4/EX4.10 | |
| parent | d1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff) | |
| download | Scilab-TBC-Uploads-master.tar.gz Scilab-TBC-Uploads-master.tar.bz2 Scilab-TBC-Uploads-master.zip | |
Diffstat (limited to '3886/CH4/EX4.10')
| -rw-r--r-- | 3886/CH4/EX4.10/4_10.txt | 9 | ||||
| -rw-r--r-- | 3886/CH4/EX4.10/Ex4_10.sce | 33 |
2 files changed, 42 insertions, 0 deletions
diff --git a/3886/CH4/EX4.10/4_10.txt b/3886/CH4/EX4.10/4_10.txt new file mode 100644 index 000000000..ad3bcaa84 --- /dev/null +++ b/3886/CH4/EX4.10/4_10.txt @@ -0,0 +1,9 @@ +
+--> exec('E:\My program EM\4. Analysis of pin-jointed plane frames\Ex4_10.sce', -1)
+The required forces are:-
+Force in member AB=120 kN
+Force in member BC=56 kN
+Force in member CD=-39 kN
+Force in member DE=-40 kN
+Force in member EB=-113 kN
+Force in member BD=40 kN
\ No newline at end of file diff --git a/3886/CH4/EX4.10/Ex4_10.sce b/3886/CH4/EX4.10/Ex4_10.sce new file mode 100644 index 000000000..24552c8fe --- /dev/null +++ b/3886/CH4/EX4.10/Ex4_10.sce @@ -0,0 +1,33 @@ +//Finding unknown forces
+//Refer fig. 4.8
+//Let us assume joint E as origin,EC as x-axis,EA as y-direction
+//accordingly the co-ordinates are
+//A(0,3),B(3,3),C(6,0),D(3,0),E(0,0)
+YD=-40 //kN
+YC=-40 //kN
+//Using co-ordinates lengths are found out to be
+LAB=3 //m
+LBC=3*sqrt(2) //m
+LCD=3 //m
+LDE=3 //m
+LBD=3 //m
+LBE=3*sqrt(2) //m
+//Consider joint C
+//applying equilibrium conditions
+tCB=40/3
+tCD=-40/3
+FCB=tCB*LBC //kN
+FCD=-13.333*LCD //kN
+//Consider joint D
+//applying equilibrium conditions
+tDE=tCD
+FDE=tCD*LCD //kN
+tDB=40/3
+FDB=tDB*LBD
+//Consider joint B
+//applying equilibrium conditions
+tBE=-(13.333+13.333)
+FBE=tBE*LBE //kN
+tBA=40
+FBA=tBA*LAB
+printf("The required forces are:-\nForce in member AB=%.2d kN\nForce in member BC=%.2d kN\nForce in member CD=%.2d kN\nForce in member DE=%.2d kN\nForce in member EB=%.2d kN\nForce in member BD=%.2d kN",FBA,FCB,FCD,FDE,FBE,FDB)
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