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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
commit7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch)
tree449d555969bfd7befe906877abab098c6e63a0e8 /3886/CH3/EX3.6/Ex3_6.sce
parentd1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff)
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+//Determine magnitude,direction and point of application
+//refer fig.3.15(a)&(b)
+Rx=500*cosd(60)-700 //N (towards left)
+Ry=-500*sind(60)-1000-1200 //N (Downwards)
+R=sqrt((Rx^2)+(Ry^2)) //N
+alpha=atand(-Ry/Rx) //degree
+//taking moment about O
+MO=-500*300*sind(60)-1000*150+1200*150*cosd(60)-700*300*sind(60)
+//let point of application of resultant be at a distance of x from point O along the horizontal then
+x=MO/Ry //mm
+printf("The Resultant is R=%.1f N as shown in fig.3.15",R)