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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
commit7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch)
tree449d555969bfd7befe906877abab098c6e63a0e8 /3886/CH20/EX20.7/20_7.sce
parentd1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff)
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+//A flywheel
+omega0=41.888 //rad/sec
+omega=29.322 //rad/sec
+t=120 //sec
+//Kinematic equation gives
+alpha=(29.3224-41.888)/(120) //rad/sec^2
+//Weight of flywheel
+Wf=50000 //N
+//Radius of gyration
+k=1 //m
+I=(50000/9.81) //kg-m^2
+//(1) Retarding torque acting on the flywheel Tr
+Tr=5096.84*0.1047 //N-m
+//(2) Change in K.E.
+C.K.E=(5096.84*((41.888^2)-(27.322^2)))/(2) //N-m The answer provided in the textbook is wrong
+//(3) Change in its angular momentum
+C.A.M=5096.84*(41.888-29.322) //N-sec
+printf("\nRetarding torque acting on the flywheel Tr=%.3f N-m\nChange in K.E.=%.3f N-m\nChange in its angular momentum=%.3f N-sec",Tr,C.K.E,C.A.M)
+
+