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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
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+//Determining the resultant
+clc
+//Given-
+//inclination of 200N force with x axis calculated by using slope of 200N force as shown in fig.2.8
+theta1=atand(1/2) //degree
+//inclination of 120N force with x axis calculated by using slope of 120N force as shown in fig.2.8
+theta2=atand(4/3) //degree
+//summation of forces in X direction
+Fx=200*cosd(26.565)-120*cosd(53.13)-50*cosd(60)+100*sind(40) //N
+//summation of forces in Y direction
+Fy=200*sind(26.565)+120*sind(53.13)-50*sind(60)-100*cosd(40) //N
+//Resultant
+R=sqrt((Fx)^2+(Fy)^2) //N
+//inclination of resultant w.r.t X axis
+alpha=atand(65.5/146.2) //degree
+printf("The resultant of given forces :-\nR=%.1f N.\n",R)
+printf("Inclination of resultant w.r.t X-axis :-\nalpha=%.1f degree.",alpha)