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| author | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
| commit | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch) | |
| tree | 449d555969bfd7befe906877abab098c6e63a0e8 /3886/CH2/EX2.19/Ex2_19.sce | |
| parent | d1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff) | |
| download | Scilab-TBC-Uploads-master.tar.gz Scilab-TBC-Uploads-master.tar.bz2 Scilab-TBC-Uploads-master.zip | |
Diffstat (limited to '3886/CH2/EX2.19/Ex2_19.sce')
| -rw-r--r-- | 3886/CH2/EX2.19/Ex2_19.sce | 21 |
1 files changed, 21 insertions, 0 deletions
diff --git a/3886/CH2/EX2.19/Ex2_19.sce b/3886/CH2/EX2.19/Ex2_19.sce new file mode 100644 index 000000000..609b37097 --- /dev/null +++ b/3886/CH2/EX2.19/Ex2_19.sce @@ -0,0 +1,21 @@ +//determine tension and inclination
+//Refer fig. 2.24 (a),(b) and (c)
+//consider equilibrium at point B,we get
+//T2*sind(theta)=T1*sind(30)...(1)
+//T2*cosd(theta)=T1*sind(30)-20...(2)
+//consider equilibrium at point C,we get
+//T2*sind(theta)=T3*sind(60)...(3)
+//T2*cosd(theta)=-T3*cosd(60)+25...(4)
+//solving (1) and (3) we get
+//T1=T3*sqrt(3)...(5)
+//solving (2) and (4) and substituting (5) we get
+T3=45/2 //kN
+T1=T3*sqrt(3) //kN
+//then (1)/(2) gives
+theta=atand(1.416) //degree
+T2=19.48/sind(theta) //kN
+printf("\nThe required values are:-\nT1=%.2f kN\nT2=%.2f kN\nT3=%.2f kN\ntheta=%.2f degree",T1,T2,T3,theta)
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