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| author | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
| commit | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch) | |
| tree | 449d555969bfd7befe906877abab098c6e63a0e8 /3886/CH2/EX2.14/2_14.txt | |
| parent | d1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff) | |
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Diffstat (limited to '3886/CH2/EX2.14/2_14.txt')
| -rw-r--r-- | 3886/CH2/EX2.14/2_14.txt | 47 |
1 files changed, 47 insertions, 0 deletions
diff --git a/3886/CH2/EX2.14/2_14.txt b/3886/CH2/EX2.14/2_14.txt new file mode 100644 index 000000000..7a8b93f7d --- /dev/null +++ b/3886/CH2/EX2.14/2_14.txt @@ -0,0 +1,47 @@ + --> // Finding magnitude of F
+--> //When F is applied at point B,refer fig 2.18(a)and(b)
+--> //From triangle AOC
+--> OC=300-150
+ OC =
+
+ 150.
+--> AO=300
+ AO =
+
+ 300.
+--> alpha=acosd(OC/AO) //degree
+ alpha =
+
+ 60.
+--> //from triangle AOB using geometry we get angle OBA=30 degree
+--> //Resolving the forces we get
+--> R=2000/cosd(30) //N
+ R =
+
+ 2309.4011
+--> F=R*sind(30) //N
+ F =
+
+ 1154.7005
+--> printf("Least force through point B is F=%.1f N",F)
+Least force through point B is F=1154.7 N--> //Least force required through the centre of roller
+--> //Assume that F makes an angle theta with the horizontal
+--> //Refer fig. 2.19 (a) and (b)
+--> //Resolving the forces we get
+--> //F*cosd(theta)=R*sind(60)...(1)
+--> //F*sind(theta)+R*cosd(60)=W...(2)
+--> //Solving (1) and (2) we get
+--> //sind(theta)+cotd(60)*cosd(theta)=W/F
+--> //For obtaining maximum value of W/F we differentiate W/F w.r.t. theta and we get
+--> theta=acotd(cotd(60)) //degree
+ theta =
+
+ 60.
+--> //Least value of F is observed when it is at right angle to reaction R
+--> Fmin=2000*sind(60) //N
+ Fmin =
+
+ 1732.0508
+--> printf("\nLeast force through the centre of roller is Fmin=%.0f N",Fmin)
+
+Least force through the centre of roller is Fmin=1732 N
\ No newline at end of file |