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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
commit7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch)
tree449d555969bfd7befe906877abab098c6e63a0e8 /3886/CH17/EX17.16/17_16.sce
parentd1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff)
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+//Bullet fired horizontally
+//refer fig. 17.14
+//Let the velocity of the block be u immediately after bullet strikes it
+//Applying work energy principle
+u=1.025 //m/sec
+//Let v be the velocity of the bullet before striking the block
+//Principle of conservation of momentum gives
+v=342.69 //m/sec
+//Initial energy of bullet Ei
+Ei=(0.3*342.69^2)/(2*9.81) //J
+//Energy of the block and the bullet system E
+E=((100+0.3)*1.025^2)/(9.81*2) //J
+//Loss of energy El
+El=1795.68-5.37 //J
+printf("\nv=%.3f m/sec\nLoss of energy=%.3f J",v,El)
+
+
+