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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
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+//Power of a locomotive
+//refer fig.16.7 (a) and (b)
+v=(56*1000)/(60*60) //m/sec
+F=5*420/1000 //kN
+W=420 //kN
+P=F+W*(1/120) //kN
+//Power of Locomotive Pw
+Pw=P*v //kW (mistake in book)
+u=15.556 //m/sec
+//Resultant force parallel to the plane R
+R=F+W*sind(theta) //kN (Down the plane)
+s=((420*(15.556^2))/(2*9.81*5.6)) //m
+printf("Power of locomotive=%.4f kW\ns=%.4f m",Pw,s)
+//The answers vary due to round off error
+
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