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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
commit7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch)
tree449d555969bfd7befe906877abab098c6e63a0e8 /3886/CH16/EX16.10/16_10.sce
parentd1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff)
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+//Body A
+//refer fig. 16.14
+mu=0.2
+//let theta1 and theta2 be the slopes of the inclined planes
+//sind(thets1)=4/5 cosd(theta1)=0.6
+//sind(theta2)=3/5 cosd(theta2)=0.8
+//1500*sind(theta1)=1200 N down the plane
+F1=mu*1500*0.6 //N up the plane
+F2=0.2*2000*0.8 //N down the plane
+//Equating work done to change in kinetic energy
+//v=3 m/sec
+s=((1500*3*3+2000*1.5*1.5)/(2*9.81*260)) //m
+printf("\nThus s=%.3f m",s)
+
+
+