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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
commit7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch)
tree449d555969bfd7befe906877abab098c6e63a0e8 /3886/CH15/EX15.11/15_11.sce
parentd1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff)
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+//Tension in the string and accelerations of blocks
+//refer fig. 15.13 (a),(b) and (c)
+//Considering 1500 N block
+//2*T+(1500*a)/(9.81)=1500
+//Considering 500N block
+//T-(2*500*a)/(9.81)=500
+//Solving this we get
+a=(500*9.81)/(1500+2000) //m/sec^2
+T=(1500-((1500*1.401)/(9.81)))/2 //N
+printf("\na=%.3f m/sec^2\nT=%.2f N",a,T)
+