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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
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+//Two bodies hung to the rope ends
+//refer fig. 15.12 (a),(b) and (c)
+//Let a be the acceleration with which the system moves and T be the tension in the string
+//Considering 300 N body
+//T-(300*a)/(9.81)=300
+//Considering 450 N body
+//T+(450*a)/(9.81)=450
+//solving we get
+a=(450-300)*9.81/(450+300) //m/sec^2
+T=300+((300*1.962)/(9.81)) //N
+printf("\na=%.4f m/sec^2\nT=%.0f N",a,T)