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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
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tree449d555969bfd7befe906877abab098c6e63a0e8 /3886/CH12/EX12.7/12_7.sce
parentd1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff)
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+//motorist and traffic light
+//initial velocity
+u=(80*1000)/(60*60) //m/sec
+t=10 //sec
+s=200 //m
+//a be acceleration
+//using equation of motion
+a=(200-22.22*10)*2/10^2 //m/sec^2
+//final velocity
+v=(22.22-0.444*10)*(3600/1000) //kmph
+printf("\na=%.2f m/sec^2\nv=%.2f kmph",a,v)
+
+