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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//Book - Power system: Analysisi & Design 5th Edition
+//Authors - J. Duncan Glover, Mulukutla S. Sarma, and Thomas J.Overbye
+//Chapter-3 ;Example 3.12
+//Scilab Version - 6.0.0; OS - Windows
+
+clc;
+clear;
+
+Sr=1000 //rated power of transformer in kVA
+V1rated=13.8 //rated voltage of delta winding of transformer in kV
+V2rated=345 //rated voltage of wye winding of transformer in kV
+Zeq=%i*0.10 //per unit equivalent impedance
+Sb=500 //rated power of transformer in MVA
+VbXLL=13.8 //line to line X terminal base voltage in kV
+VbHLL=345 //line to line H terminal base voltage in kV
+
+
+at=(V1rated/V2rated) //ratio of transformer corresponding to rated tap
+b=(VbXLL/VbHLL)
+c=at/b
+Zpunew=Zeq*(Sb/Sr) //per unit equivalent impedance
+at10=(V1rated/(V2rated*0.9)) //ratio of transformer corresponding to 10 percentage tap
+b10=(V1rated/V2rated)
+c10=(at10/b10)
+Yeq=(1/Zpunew)
+Y12=c10*Yeq //admittance at node 12 in per unit
+Y11=(1-c10)*Yeq //admittance at node 11 in per unit
+Y22=(((abs(c10))^2)-c10)*Yeq //admittance at node 22 in per unit
+
+
+printf('The per unit equivalent impedance is %.4fi pu\n',imag(Zpunew));
+printf('The ratio of transformer corresponding to rated tap is %.4f\n',at);
+printf('The ratio of transformer corresponding to 10 percentage tap is %.4f\n',at10);
+printf('The admittance at node 12 is %.4fi per unit\n',imag(Y12));
+printf('The admittance at node 11 is %.4fi per unit\n',imag(Y11));
+printf('The admittance at node 22 is %.4fi per unit\n',imag(Y22));
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