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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
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+//===========================================================================
+//chapter 10 example 15
+clc;clear all;
+
+//variable declaration
+P = 200; //resistance in arm in Ω
+Q = 200; //resistance in arm in Ω
+S = 200; //resistance in arm in Ω
+
+R = 200; //resistance in arm in Ω
+p = 0.5; //power in W
+r = 2; //r is internal resistance of battery in Ω
+E = 24; //voltage in V
+
+//calculations
+//P = (I^2)*R; power disiipation in W
+I = sqrt(p/R);
+V = I*2*R; //the maximum voltage ,that can be appliedto the bridge in V
+I1 = 2*I; //current through series resistor in A
+//E = V+(2*I*(r+R) battery emf E
+R1 = ((E-V)/I1)-r; //series resistance in Ω
+
+//result
+mprintf("current = %3.2f A",I);
+mprintf("\nseries resistance = %3.2f Ω",R1);