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author | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
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committer | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
commit | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch) | |
tree | 449d555969bfd7befe906877abab098c6e63a0e8 /3864/CH8/EX8.12 | |
parent | d1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff) | |
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Diffstat (limited to '3864/CH8/EX8.12')
-rw-r--r-- | 3864/CH8/EX8.12/Ex8_12.sce | 43 |
1 files changed, 43 insertions, 0 deletions
diff --git a/3864/CH8/EX8.12/Ex8_12.sce b/3864/CH8/EX8.12/Ex8_12.sce new file mode 100644 index 000000000..0a29dbff5 --- /dev/null +++ b/3864/CH8/EX8.12/Ex8_12.sce @@ -0,0 +1,43 @@ +clear +// +// + +//Initilization of Variables + +d_o=300 //mm //Outside diameter +d2=200 //mm //Internal Diameter +p=12 //N/mm**2 //internal Fluid pressure +F_max=16 //N/mm**2 //Tensile stress +r_o=150 //mm //Outside Diameter +r2=100 //mm //Internal Diameter + +//Calculations + +//Let p_o be the External Pressure applied. +//From LLame's theorem +//p_x=b*(x**2)**-1-a ..............(1) +//F_x=b*(x**2)**-1+a ...........................(2) + +//Now At +x=100 //mm +p_x=12 //N/mm**2 +//sub in equation 1 we get +//12=b*(100**2)**-1-a . ..................(3) + +//The Max Hoop stress occurs at least value of x where +//16=b*(100**2)**-1+a .......................(4) + +//From Equations 1 and 2 we get +//28=b*(100**2)**-1+b*(100**2)**-1 +//After furhter Simplifying we get +b=28*100**2*2**-1 + +//sub in equation 1 we get +a=-(12-(b*(100**2)**-1)) + +//Thus At +x2=150 //mm +p_o=b*(x2**2)**-1-a + +//Result +printf("\n Minimum External applied is %0.2f N/mm**2",p_o) |