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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
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parentd1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff)
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+clear
+//
+//
+
+//Initilization of Variables
+
+P=245*10**6 //N-mm/sec //Power transmitted
+n=240 //rpm
+q_s=40 //N/mm**2 //Shear stress
+theta=%pi*180**-1 //radian //Angle of twist
+L=1000 //mm //Length of shaft
+G=80*10**3 //N/mm**2
+
+//Tmax=1.5*T
+
+//Calculations
+
+T=P*60*(2*%pi*n)**-1 //N-mm //Torsional Moment
+Tmax=1.5*T
+
+//Now For Solid shaft
+//J=%pi*32*d**4
+
+//Now from the consideration of shear stress we get
+//T*J**-1=q_s*(d*2**-1)**-1
+//After substituting value in above Equation we get
+//T=%pi*16**-1*d**3*q_s
+
+//Designing For max Torque
+d=(Tmax*16*(%pi*40)**-1)**0.33333 //mm //Diameter of shaft
+
+//For max Angle of Twist
+//Tmax*J**-1=G*theta*L**-1
+//After substituting value in above Equation we get
+d2=(Tmax*32*180*L*(%pi**2*G)**-1)**0.25
+
+//For Hollow Shaft
+
+//d1_2=Outer Diameter
+//d2_2=Inner Diameter
+
+//d2_2=0.5*d1_2
+
+// Polar modulus
+//J=%pi*32**-1*(d1_2**4-d2_2**4)
+//After substituting values we get
+//J=0.092038*d1_2**4
+
+//Now from the consideration of stress
+//Tmax*J**-1=q_s*(d1_2*2**-1)**-1
+//After substituting values and further simplifying we get
+d1_2=(Tmax*(0.092038*2*q_s)**-1)**0.33333
+
+//Now from the consideration of angle of twist
+//Tmax*J**-1=G*theta*L**-1
+//After substituting values and further simplifying we get
+d1_3=(Tmax*180*L*(0.092038*G*%pi)**-1)**0.25
+
+d2_2=0.5*d1_2
+
+//result
+printf("\n Diameter of shaft is:For solid shaft:d %0.2f mm",d)
+printf("\n :For Hollow shaft:d1_2 %0.3f mm",d1_2)
+printf("\n : :d2_2 %0.3f mm",d2_2)