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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
commit7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch)
tree449d555969bfd7befe906877abab098c6e63a0e8 /3864/CH6/EX6.23/Ex6_23.sce
parentd1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff)
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+clear
+//
+//
+
+//Initilization of Variables
+
+K=5 //N/mm //Stiffness
+L=100 //mm //Solid Length
+q_s=60 //N/mm**2 //Max shear stress
+W=200 //N //Max Load
+G=80*10**3 //N/mm**2
+
+//Calculations
+
+//K=W*dell**-1
+//After substituting values and further simplifying we get
+//d=0.004*R**3*n ........(1) //mm //Diameter of wire
+//n=L*d**-1 ........(2)
+
+//From Shearing stress
+//q_s=16*W*R*(%pi*d**3)**-1
+//After substituting values and further simplifying we get
+//d**4=0.004*R**3*n .................(4)
+
+//From Equation 1,2,3
+//d**4=0.004*(0.0785*d**3)**3*100*d**-1
+//after further simplifying we get
+d=5168.101**0.25
+n=100*d**-1
+R=(d**4*(0.004*n)**-1)**0.3333
+
+//Result
+printf("\n Diameter of Wire is %0.2f mm",d)
+printf("\n No.of turns is %0.2f ",n)
+printf("\n Mean Radius of spring is %0.2f mm",R)