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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
commit7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch)
tree449d555969bfd7befe906877abab098c6e63a0e8 /3864/CH4/EX4.7/Ex4_7.sce
parentd1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff)
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+clear
+//
+
+//Initilization of Variables
+
+F=12 //KN //Force at End of beam
+L=2 //m //span
+
+//Square section
+b=200 //mm //Width and depth of beam
+d=200
+
+//Rectangular section
+b1=150 //mm //Width
+d1=300 //mm //Depth
+
+//Calculations
+
+//Max bending Moment
+M=F*L*10**6 //N-mm
+
+//M=sigma*b*d**2
+sigma=M*6*(b*d**2)**-1 //N/mm**2
+
+//Let W be the central concentrated Load in simply supported beam of span L1=3 m
+//MAx Moment
+//M1=W*L1*4**-1
+//After Further simplifying we get
+//M1=0.75*10**6 //N-mm
+
+//The section has a moment of resistance
+M1=sigma*1*6**-1*b1*d1**2
+
+//Equating it to moment of resistance we get max load W
+//0.75*10**6*W=M1
+//After Further simplifying we get
+W=M1*(0.75*10**6)**-1
+
+//Result
+printf("\n Minimum Concentrated Load required to brek the beam %0.2f KN",W)