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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
commit7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch)
tree449d555969bfd7befe906877abab098c6e63a0e8 /3862/CH9/EX9.1/Ex9_1.sce
parentd1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff)
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+clear
+//
+
+//variable declaration
+
+//summation of all horizontal forces is zero & vertical forces is zero.
+P1=(10) //Vertical down Load at 4m from A,KN
+P2=(15) //Inclined down Load at angle 30° at 6m from A,KN
+P3=(20) //Inclined down Load at angle 45° at 10m from A,KN
+theta2=30
+theta3=45
+//horizontal,vertical component at A is Ha,Va respectively.
+
+Ha=P2*cos(theta2*%pi/180)+P3*cos(theta3*%pi/180)
+Rb=(P1*4+P2*6*sin(theta2*%pi/180)+P3*10*sin(theta3*%pi/180))/12 //reaction at B point,KN
+
+printf("\n RB= %0.4f KN",Rb)
+
+//now vertical component
+Va=P2*sin(theta2*%pi/180)+P3*sin(theta3*%pi/180)+P1-Rb
+
+Ra=sqrt((Ha**2)+(Va**2))
+
+printf("\n RA= %0.4f KN",Ra)
+
+alpha=(atan(Va/Ha))*180/%pi
+
+printf("\n alpha= %0.2f °",alpha)