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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
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tree449d555969bfd7befe906877abab098c6e63a0e8 /3862/CH8/EX8.15/Ex8_15.sce
parentd1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff)
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+clear
+//variable declaration
+// Let the x, y, z be the mutually perpendicular directions
+
+pr=(0.3)
+PX=(15) //Loading in x-direction,KN
+PY=(80) //Loading in Y-direction(compressive),KN
+PZ=(180) //Loading in Z-direction,KN
+
+//Area in X-,Y-,Z-Direction is AX,AY,AZ respectively,mm^2
+
+AX=(10*30)
+AY=(10*400)
+AZ=(30*400)
+
+//stress devoloped in X-,Y-,Z- direction as px,py,pz respectively,N/mm^2
+
+px=PX*1000/AX
+py=PY*1000/AY
+pz=PZ*1000/AZ
+
+//Noting that a stress produces a strain of p/E in its own direction, the nature being same as that of stress and ยต p E in lateral direction of opposite nature, and taking tensile stress as +ve, we can write expression for strains ex, ey, ez.
+E=2*100000 //young's modulus,N/mm^2
+
+ex=(px/E)+(pr*py/E)-(pr*pz/E)
+ey=(-pr*px/E)-(py/E)-(pr*pz/E)
+ez=(-pr*px/E)+(pr*py/E)+(pz/E)
+
+ev=ex+ey+ez //Volumetric strain
+
+volume=10*30*400
+
+Changeinvolume=ev*volume
+
+printf("\n Change in volume= %0.2f mm^3",Changeinvolume)