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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
commit7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch)
tree449d555969bfd7befe906877abab098c6e63a0e8 /3862/CH4/EX4.10/Ex4_10.sce
parentd1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff)
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Added new codeHEADmaster
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+clear
+// If xc and yc are the coordinates of the centre of the circle, centroid also must have the coordinates xc and yc as per the condition laid down in the problem. The shaded area may be considered as a rectangle of size 200 mm × 150 mm minus a triangle of sides 100 mm × 75 mm and a circle of diameter 100 mm.
+
+//
+//variable declaration
+
+Ap=200.0*150.0 //Area of plate,mm^2
+At=100.0*75.0/2.0 //Area of triangle,mm^2
+Ah=%pi*(100**2)/4.0 //Area of hole **mm^2
+
+A=Ap-At-Ah
+
+
+X1=100.0
+X2=200.0-100.0/3.0
+//X3=Xc
+
+Y1=75.0
+Y2=150.0-25.0
+//Y3=Yc
+
+A=Ap-At-Ah
+
+xc=(Ap*X1-At*X2)/(Ah+A)
+
+printf("\n xc= %0.2f mm",xc)
+
+yc=(Ap*Y1-At*Y2)/(Ah+A)
+
+printf("\n yc= %0.2f mm",yc)