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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
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tree449d555969bfd7befe906877abab098c6e63a0e8 /3862/CH2/EX2.28/Ex2_28.sce
parentd1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff)
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+clear
+//
+
+//variable declaration
+W=600.0 //weight of cyclinder,N
+r=150.0 //radius of cylinder,mm
+a=600.0 //mm
+b=300.0 //mm
+
+//Free body diagram of sphere and frame
+
+////sum of vertical Fy & sum of horizontal forces Fx is zero
+//Assume direction of Fx is right
+//Assume direction of Fy is up
+
+RB=600.0
+//As the frame is in equilibrium under the action of three forces only, they must be concurrent forces. In other words, reaction at D has line of action alone OD. Hence, its inclination to horizontal is given by:
+printf("\n RB= %0.2f N",RB)
+alpha=atan((a-r)/r)
+printf("\n alpha= %0.4f °",alpha)
+
+RD=W/sin(alpha)
+printf("\n RD= %0.3f N",RD)
+
+RC=RD*cos(alpha)
+RA=RC
+printf("\n RC= %0.0f N",RC)
+printf("\n RA= %0.0f N",RA)