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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
commit7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch)
tree449d555969bfd7befe906877abab098c6e63a0e8 /3862/CH2/EX2.13/Ex2_13.sce
parentd1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff)
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+clear
+//
+
+//variable declaration
+
+PB=20.0 //loading at B,KN
+PC=30.0 //loading at C,KN
+PD=40.0 //loading at D,KN
+PA=60.0 //loading at E,KN
+AB=1.0
+BC=2.0
+CD=1.0
+//length are in m
+
+// Let x and y axes be selected
+//sum of vertical Fy & sum of horizontal forces Fx is zero
+//Assume direction of Fx is right
+//Assume direction of Fy is up
+Rx=0
+Ry=PA+PB+PC+PD
+
+R=sqrt((Rx**2)+(Ry**2))
+printf("\n R= %0.2f KN",R)
+
+
+//Taking clockwise moment as positive,
+//sum of moment at A
+
+MA=(0)*PA+(AB)*PB+PC*(AB+BC)+PD*(AB+BC+CD)
+printf("\n MA= %0.2f KN-m",MA)
+
+// The distance of resultant from A is,
+
+x=MA/R
+printf("\n x= %0.1f m",x)