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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3856/CH11/EX11.5 | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3856/CH11/EX11.5')
-rw-r--r-- | 3856/CH11/EX11.5/Ex11_5.sce | 28 | ||||
-rw-r--r-- | 3856/CH11/EX11.5/Ex11_5.txt | 1 |
2 files changed, 29 insertions, 0 deletions
diff --git a/3856/CH11/EX11.5/Ex11_5.sce b/3856/CH11/EX11.5/Ex11_5.sce new file mode 100644 index 000000000..150d241e3 --- /dev/null +++ b/3856/CH11/EX11.5/Ex11_5.sce @@ -0,0 +1,28 @@ +//Describe how you would prepare a phosphate buffer with a pH of seven point four
+
+//Example 11.5
+
+clc;
+
+clear;
+
+Ka1=7.5*10^-3; //Equilibrium consatnt for H3PO4= H+ +H2PO4-
+
+pKa1=-log10(Ka1); //minus logerithm of Ka1
+
+Ka2=6.2*10^-8; //Equilibrium consatnt for H2PO4-= H+ +HPO4--
+
+pKa2=-log10(Ka2); //minus logerithm of Ka2
+
+Ka3=4.8*10^-13; //Equilibrium consatnt for HPO4-- = H+ +PO3---
+
+pKa3=-log10(Ka3); //minus logerithm of Ka3
+
+pH=7.40; //pH of the required buffer solution
+
+C1=10^(pH-pKa2); //Concentratin of required solution to prepare buffer solution of pH of 7.40
+
+C=C1/1.0; //Ratio of the required solution to prepare buffer solution of pH of 7.40
+
+printf("Ratio of the required solution = %.2f The buffer is dissolve to disodium hydrogen phosphate and sodium dihydrogen phosphate in a mole ratio of 1.5:1.0 ",C);
+
diff --git a/3856/CH11/EX11.5/Ex11_5.txt b/3856/CH11/EX11.5/Ex11_5.txt new file mode 100644 index 000000000..c26d903e9 --- /dev/null +++ b/3856/CH11/EX11.5/Ex11_5.txt @@ -0,0 +1 @@ + Ratio of the required solution = 1.56 The buffer is dissolve to disodium hydrogen phosphate and sodium dihydrogen phosphate in a mole ratio of 1.5:1.0
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