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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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treedbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3845/CH4
parentb1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff)
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-rw-r--r--3845/CH4/EX4.1/Ex4_1.sce7
-rw-r--r--3845/CH4/EX4.10/Ex4_10.sce10
-rw-r--r--3845/CH4/EX4.2/Ex4_2.sce10
-rw-r--r--3845/CH4/EX4.3/Ex4_3.sce9
-rw-r--r--3845/CH4/EX4.4/Ex4_4.sce11
-rw-r--r--3845/CH4/EX4.5/Ex4_5.sce13
-rw-r--r--3845/CH4/EX4.6/Ex4_6.sce11
-rw-r--r--3845/CH4/EX4.7/Ex4_7.sce20
-rw-r--r--3845/CH4/EX4.8/Ex4_8.sce14
-rw-r--r--3845/CH4/EX4.9/Ex4_9.sce13
10 files changed, 118 insertions, 0 deletions
diff --git a/3845/CH4/EX4.1/Ex4_1.sce b/3845/CH4/EX4.1/Ex4_1.sce
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+//Example 4.1
+F_net=51;//Net external force (N)
+m=24;//Mass of the mower (kg)
+a=F_net/m;//Acceleration (m/s^2)
+printf('Acceleration = %0.1f m/s^2',a)
+//Openstax - College Physics
+//Download for free at http://cnx.org/content/col11406/latest
diff --git a/3845/CH4/EX4.10/Ex4_10.sce b/3845/CH4/EX4.10/Ex4_10.sce
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index 000000000..47dc7d4ef
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+++ b/3845/CH4/EX4.10/Ex4_10.sce
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+//Example 4.10
+delta_v=8;//Velocity change (m/s)
+delta_t=2.5;//Time period (s)
+a=delta_v/delta_t;//Acceleration (m/s^2)
+printf('a.Average acceleration = %0.2f m/s^2',a)
+m=70;//Player's mass (kg)
+F_net=m*a;//Force exerted (N)
+printf('\nb.Average force exerted backward on the ground = %0.1f N',F_net)
+//Openstax - College Physics
+//Download for free at http://cnx.org/content/col11406/latest
diff --git a/3845/CH4/EX4.2/Ex4_2.sce b/3845/CH4/EX4.2/Ex4_2.sce
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index 000000000..3539dfc4b
--- /dev/null
+++ b/3845/CH4/EX4.2/Ex4_2.sce
@@ -0,0 +1,10 @@
+//Example 4.2
+m=2100;//Mass of the system (kg)
+a=49;//Initial acceleration (m/s^2)
+f=650;//Frictional force (N)
+T=(m*a+f)/4;//Thrust exerted by each rocket (N), See Equation 4.14
+//There are 4 rockets. Net horizontal force F_net=m*a (N)
+printf('Individual thrust exerted by each rocket = %0.1e N',T)
+//Openstax - College Physics
+//Download for free at http://cnx.org/content/col11406/latest
+
diff --git a/3845/CH4/EX4.3/Ex4_3.sce b/3845/CH4/EX4.3/Ex4_3.sce
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index 000000000..926399fb9
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+++ b/3845/CH4/EX4.3/Ex4_3.sce
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+//Example 4.3
+F_floor=150;//Backward force exerted (N)
+f=24;//Net opposing force (N)
+m=65+12+7;//Total mass of System 1, mass of professor+mass of cart+mass of equipment, (kg)
+F_net=F_floor-f;//Net force (N)
+a=F_net/m;//Acceleration (m/s^2)
+printf('Acceleration = %0.1f m/s^2',a)
+//Openstax - College Physics
+//Download for free at http://cnx.org/content/col11406/latest
diff --git a/3845/CH4/EX4.4/Ex4_4.sce b/3845/CH4/EX4.4/Ex4_4.sce
new file mode 100644
index 000000000..7c39012f9
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+++ b/3845/CH4/EX4.4/Ex4_4.sce
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+//Example 4.4
+//Also see Example 4.3
+m=12+7;//Total mass of System 2, mass of cart+mass of equipment, (kg)
+a=1.5;//Acceleration (m/s^2), See Example 4.3
+F_net=m*a;//Net external force (N)
+f=24;//Net opposing force (N)
+F_prof=F_net+f;//Force exerted by the professor on the cart (N)
+printf('Force exerted by the professor on the cart = %0.1f N',F_prof)
+//Answer varies due to round off error
+//Openstax - College Physics
+//Download for free at http://cnx.org/content/col11406/latest
diff --git a/3845/CH4/EX4.5/Ex4_5.sce b/3845/CH4/EX4.5/Ex4_5.sce
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index 000000000..7cfbc4953
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+++ b/3845/CH4/EX4.5/Ex4_5.sce
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+//Example 4.5
+m=60;//Mass of the skier and equipment (kg)
+theta=25;//Angle of inclination (deg)
+g=9.8;//Acceleration due to gravity (m/s^2)
+F_net_p=m*g*sind(theta);//Net force parallel to the slope (N)
+a_p=F_net_p/m;//Acceleration (m/s^2)
+printf('a.Acceleration (disregarding friction) = %0.2f m/s^2', a_p)
+f=45;//Frictional force (N)
+F_net_p_b=m*g*sind(theta)-f;//Net force parallel to the slope considering friction (N)
+a_p_b=F_net_p_b/m;//Acceleration (m/s^2)
+printf('\nb.Acceleration (considering friction) = %0.2f m/s^2', a_p_b)
+//Openstax - College Physics
+//Download for free at http://cnx.org/content/col11406/latest
diff --git a/3845/CH4/EX4.6/Ex4_6.sce b/3845/CH4/EX4.6/Ex4_6.sce
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index 000000000..781bdaa3c
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+++ b/3845/CH4/EX4.6/Ex4_6.sce
@@ -0,0 +1,11 @@
+//Example 4.6
+m=70;//Mass of the tightrope walker (kg)
+theta=5;//Angle (deg)
+g=9.8;//Acceleration due to gravity (m/s^2)
+w=m*g;//Weight of the tightrope walker (N)
+T=w/(2*sind(theta));//Tension (N), See Equation 4.52
+//See textbook for derivation
+printf('Tension in the wire = %0.1f N',T)
+//Answer varies due to round off error
+//Openstax - College Physics
+//Download for free at http://cnx.org/content/col11406/latest
diff --git a/3845/CH4/EX4.7/Ex4_7.sce b/3845/CH4/EX4.7/Ex4_7.sce
new file mode 100644
index 000000000..4aef6a974
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+++ b/3845/CH4/EX4.7/Ex4_7.sce
@@ -0,0 +1,20 @@
+//Example 4.7
+Fx=2.7*10^5;//Force exerted in the x-direction (N)
+Fy=3.6*10^5;//Force exerted in the y-direction (N)
+m=5*10^6;//Mass of the barge (kg)
+a=7.5*10^-2;//Acceleration (m/s^2)
+theta=53.1;//Angle (deg)
+F_app=sqrt(Fx^2+Fy^2);//Resultant applied force (N)
+theta=atand(Fy/Fx);//Direction of resultant applied force (deg)
+F_net=m*a;//Net external force (N)
+F_D=F_app-F_net;//Drag force (N)
+printf('Drag force exerted by water = %0.1e N',F_D)
+printf('\nDirection of the drag force is opposite to that of the applied force.')
+//Direction of drag force, theta_F_D=53 deg south of west
+//also it may be noted that if theta_F_D is to be measured from the same reference axis as theta
+//theta_F_D=theta+180;
+//if theta_F_D>360
+// theta_F_D=theta_F_D-360;
+//end
+//Openstax - College Physics
+//Download for free at http://cnx.org/content/col11406/latest
diff --git a/3845/CH4/EX4.8/Ex4_8.sce b/3845/CH4/EX4.8/Ex4_8.sce
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index 000000000..5fd91c1ff
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+//Example 4.8
+m=15;//Mass of traffic light (kg)
+g=9.8;//Acceleration due to gravity (m/s^2)
+w=m*g;//Weight of traffic light (N)
+theta1=30;//Angle for wire 1 (deg)
+theta2=45;//Angle for wire 2 (deg)
+T1=w/(sind(theta1)+[cosd(theta1)/cosd(theta2)]*sind(45));//Tension in wire 1 (N), Substitute Equation 4.69 in Equation 4.73
+//See textbook for derivation
+printf('Tension in wire 1 = %0.1f N',T1)
+T2=[cosd(theta1)/cosd(theta2)]*T1;//Tension in wire 2 (N), See Equation 4.69
+printf('\nTension in wire 2 = %0.1f N',T2)
+//Answer varies due to round off error
+//Openstax - College Physics
+//Download for free at http://cnx.org/content/col11406/latest
diff --git a/3845/CH4/EX4.9/Ex4_9.sce b/3845/CH4/EX4.9/Ex4_9.sce
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index 000000000..2763fbf28
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+//Example 4.9
+m=75;//Mass of the man (kg)
+g=9.8;//Acceleration due to gravity (m/s^2)
+a=1.20;//Upward acceleration of the elevator (m/s^2)
+F_s=m*a+m*g;//Force as measured by the scale (N)
+printf('a.Force as measured by the scale when the elevator is accelerating upwards = %0.1f N',F_s)
+//Discussion
+F_s1=m*g;//Force as measured by the scale when stationary (N)
+printf('\nDiscussion:\nForce as measured by the scale when stationary = %0.1f N',F_s1)
+F_s_b=m*g;//Force as measured by the scale when moving with constant upward velocity (N)
+printf('\nb.Force as measured by the scale when moving with constant upward velocity = %0.1f N',F_s_b)
+//Openstax - College Physics
+//Download for free at http://cnx.org/content/col11406/latest