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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+//Example 15.1
+Q=40-25;//Net heat transfer (J)
+W=10-4;//Net work done (J)
+delta_U=Q-W;//Change in internal energy (J)
+printf('a.Change in internal energy = %0.2f J',delta_U)
+//Another approach:
+//Q1=40;//Heat transfer into system for process 1(J)
+//W1=10;//Work done by the system for process 1 (J)
+//delta_U1=Q1-W1;//Change in internal energy for process 1 (J)
+//Q2=-25;//Heat transfer out of the system for process 2 (J)
+//W2=-4;//Work done on the system for process 2 (J)
+//delta_U2=Q2-W2;//Change in internal energy for process 2 (J)
+//delta_U=delta_U1+delta_U2;//Total change in internal energy (J)
+
+Qb=-150;//Net heat transfer (J)
+Wb=-159;//Net work done (J)
+delta_Ub=Q-W;//Change in internal energy (J)
+printf('\nb.Change in internal energy = %0.2f J',delta_Ub)
+//Openstax - College Physics
+//Download for free at http://cnx.org/content/col11406/latest
+