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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+//Example 10.15
+m=50*10^-3;//Mass of the disc (kg)
+v=30;//Initial velocity of the disc (m/s)
+M=2;//Mass of the stick (kg)
+r=1.2;//Length of the stick (m)
+I_prime=(m+M/3)*r^2;//Moment of inertia of the stick and disc stuck together, See Equation 10.128 (kg.m^2)
+omega_prime=m*v*r/I_prime;//Angular velocity (rad/s)
+printf('a.Angular velocity of the two (stick and disc) after collision = %0.2f rad/s',omega_prime)
+KE=(1/2)*m*v^2;//Initial kinetic energy (translational) (J)
+printf('\nb.Initial kinetic energy = %0.1f J',KE)
+KE_prime=(1/2)*I_prime*omega_prime^2;//Final kinetic energy (rotational) (J)
+printf('\n Final kinetic energy = %0.2f J',KE_prime)
+p=m*v;//Linear momentum before collision (kg.m/s)
+printf('\nc.Total linear momentum before collision = %0.2f kg.m/s',p)
+v_prime=r*omega_prime;//New velocity of the disk (m/s)
+p_prime=(m+M/2)*v_prime;//Linear momentum after collision (kg.m/s)
+printf('\n Total linear momentum after collision = %0.2f kg.m/s',p_prime)
+//Openstax - College Physics
+//Download for free at http://cnx.org/content/col11406/latest