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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3843/CH7/EX7.6/Ex7_6.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3843/CH7/EX7.6/Ex7_6.sce')
| -rw-r--r-- | 3843/CH7/EX7.6/Ex7_6.sce | 26 |
1 files changed, 26 insertions, 0 deletions
diff --git a/3843/CH7/EX7.6/Ex7_6.sce b/3843/CH7/EX7.6/Ex7_6.sce new file mode 100644 index 000000000..fe5777615 --- /dev/null +++ b/3843/CH7/EX7.6/Ex7_6.sce @@ -0,0 +1,26 @@ +// Example 7_6
+clc;funcprot(0);
+// Given data
+T_1=1000;// K
+P_1=0.5;// The inlet pressure in MPa
+P_2=0.1;// The exit pressure in MPa
+T_0=298;// K
+R=0.286;// kJ/kg.K
+
+// Calculation
+// From the air tables
+phi_1=2.968;// kJ/kg.K
+phi_2=phi_1-(R*log(P_1/P_2));// kJ/kg.K
+// Thus
+T_2=657.5;// K
+h_2=667.8;// kJ/kg
+h_1=1046.1;// kJ/kg
+h_0=298.2;// kJ/kg
+V_2=sqrt(2)*((h_1-h_2)*10^3)^(0.5);// m/s
+P_0=P_2;// MPa
+phi_0=1.695;// kJ/kg.K
+X_2=(h_2-h_0)+((V_2)^2/(2*1000))-(T_0*(phi_2-phi_0-(R*log(P_2/P_0))));// kJ/kg
+X_1=h_1-h_0-(T_0*(phi_1-phi_0-(R*log(P_1/P_0))));// The availability supplied in kJ/kg
+e_II=X_2/X_1;// The second law effectiveness for an ideal isentropic nozzle
+printf("\nThe second law effectiveness for an ideal isentropic nozzle,e_II=%1.2f",e_II);
+// The answer provided in the textbook is wrong
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