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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Example 4_9
+clc;funcprot(0);
+// Given data
+x=70/100;// The quality of steam
+p_1=200;// kPa
+p_2=800;// kPa
+V=2;// m^3
+v_f=0.0011;// m^3/kg
+v_fg=0.8857;// m^3/kg
+u_f1=504.5;// kJ/kg
+u_fg1=2529.5;// kJ/kg
+
+// Calculation
+v=v_f+(x*(v_fg-v_f));// m^3/kg
+m=V/v;// The mass in kg
+u_1=u_f1+(x*(u_fg1-u_f1));// The internal energy at state 1 in kJ/kg
+// From the steam tables at 800 kPa we find by extrapolation
+v_1=v;// m^3/kg
+v_2=v_1;// m^3/kg
+u_2=((0.6203-0.6181)/(0.6181-0.5601))*(3661-3476);// kJ/kg
+Q=m*(u_2-u_1);// kJ
+printf("\nThe heat transfer,Q=%4.0f kJ",Q);